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Exclude taxonomy parent when outputting in the loop?

I have places in my template where I need to display the name of a country. Right now, I have a taxonomy of "Location" that lists continent names as the parent and country names as the children. I would like to be able to list only countries (without continent names) within the loop.

This is the code I've started with:

<?php echo get_the_term_list( $post->ID, 'Location', 'Country: ', ', ', '' ); ?>

Example of what above code gives me: Country: Africa, Nigeria
where I would like: Country: Nigeria

The other thing is that I would also like to be able to output the parent category name without the children in specific locations as well.

This question has been answered.

Jeremy Phillips | 02/28/11 at 8:33pm Edit


(3) Possible Answers Submitted...

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  • avatar
    Last edited:
    02/28/11
    9:09pm
    Vidyut Kale says:

    <codel>

    <?php wp_list_categories('child_of=1&title_li=&taxonomy=location' ); ?>



    Where child_of=1 can be replaced by whichever continent's id you need.

    To output only the parent category names without children, try


    
<?php wp_list_categories('depth=1&title_li=&taxonomy=location' ); ?>

  • avatar
    Last edited:
    03/01/11
    12:13am
    rilwis says:

    You can try this code:

    $terms = get_the_terms(get_the_ID(), 'location');
    
$countries = array();
    
foreach ($terms as $term) {
    
	if ($term->parent) $countries[] = $term->name;
    
}
    
echo 'Country: ' . implode(', ', $countries);

    • 02/28/11 11:05pm

      Jeremy Phillips says:

      Thank you, that worked very well! Just one more thing, how could I show just the continent (parent) name without the children (countries)?

    • 02/28/11 11:35pm

      rilwis says:

      Just change a bit in the code:

      $terms = get_the_terms(get_the_ID(), 'location');
      
$continent = array();
      
foreach ($terms as $term) {
      
	if (0 == $term->parent) $continent[] = $term->name;
      
}
      
echo 'Continient: ' . implode(', ', $continent);

  • avatar
    Last edited:
    03/01/11
    11:00am
    Nathan Epp says:

    to @rilwis 's code you can just add a ! infront of $term->parent

    if ( !$term->parent ) $countries[] = $term->name;

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